Y^2+20y^2-8=15

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Solution for Y^2+20y^2-8=15 equation: 



^2+20Y^2-8=15

We move all terms to the left:

^2+20Y^2-8-(15)=0

determiningTheFunctionDomain
20Y^2-8-15+^2=0

We add all the numbers together, and all the variables

20Y^2=0

a = 20; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·20·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$Y=\frac{-b}{2a}=\frac{0}{40}=0$

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